Python Dictionaries
InfoDb = []
InfoDb.append({
    "FirstName": "John",
    "LastName": "Mortensen",
    "DOB": "October 21",
    "Residence": "San Diego",
    "Email": "jmortensen@powayusd.com",
    "Owns_Cars": ["2015-Fusion", "2011-Ranger", "2003-Excursion", "1997-F350", "1969-Cadillac"]
})
# Append to List a 2nd Dictionary of key/values
InfoDb.append({
    "FirstName": "Sunny",
    "LastName": "Naidu",
    "DOB": "August 2",
    "Residence": "Temecula",
    "Email": "snaidu@powayusd.com",
    "Owns_Cars": ["4Runner"]
})
InfoDb.append({
    "FirstName": "Colin",
    "LastName": "Mills",
    "DOB": "February 15",
    "Residence": "Poway",
    "Email": "colinm03478@stu.powayusd.com",
    "Owns_Cars": ["2005-Accord"]
})
InfoDb.append({
    "FirstName": "Azeem",
    "LastName": "NA",
    "DOB": "NA",
    "Residence": "NA",
    "Email": "NA",
    "Owns_Cars": ["Nissan-Leaf"]
})
# Print the data structure
values = 0
for i in InfoDb:
    print ("Values For:")
    print (InfoDb[values]['FirstName'])
    print ("Lastname:")
    print (InfoDb[values]['LastName'])
    print ("Owns Cars:")
    print (InfoDb[values]['Owns_Cars'])
    print ("Email:")
    print (InfoDb[values]['Email'])
    print ("Residence:")
    print (InfoDb[values]['Residence'])
    print ("Birth Date:")
    print (InfoDb[values]['DOB'])
    values += 1
    print()