Python Dictionaries
InfoDb = []
InfoDb.append({
"FirstName": "John",
"LastName": "Mortensen",
"DOB": "October 21",
"Residence": "San Diego",
"Email": "jmortensen@powayusd.com",
"Owns_Cars": ["2015-Fusion", "2011-Ranger", "2003-Excursion", "1997-F350", "1969-Cadillac"]
})
# Append to List a 2nd Dictionary of key/values
InfoDb.append({
"FirstName": "Sunny",
"LastName": "Naidu",
"DOB": "August 2",
"Residence": "Temecula",
"Email": "snaidu@powayusd.com",
"Owns_Cars": ["4Runner"]
})
InfoDb.append({
"FirstName": "Colin",
"LastName": "Mills",
"DOB": "February 15",
"Residence": "Poway",
"Email": "colinm03478@stu.powayusd.com",
"Owns_Cars": ["2005-Accord"]
})
InfoDb.append({
"FirstName": "Azeem",
"LastName": "NA",
"DOB": "NA",
"Residence": "NA",
"Email": "NA",
"Owns_Cars": ["Nissan-Leaf"]
})
# Print the data structure
values = 0
for i in InfoDb:
print ("Values For:")
print (InfoDb[values]['FirstName'])
print ("Lastname:")
print (InfoDb[values]['LastName'])
print ("Owns Cars:")
print (InfoDb[values]['Owns_Cars'])
print ("Email:")
print (InfoDb[values]['Email'])
print ("Residence:")
print (InfoDb[values]['Residence'])
print ("Birth Date:")
print (InfoDb[values]['DOB'])
values += 1
print()