Homework/Hacks

our homework we have decided for a decimal number to binary converter. You must use conditional statements within your code and have a input box for where the decimal number will go. This will give you a 2.7 out of 3 and you may add anything else to the code to get above a 2.7.

Below is an example of decimal number to binary converter which you can use as a starting template.

def DecimalToBinary(num):
    strs = ""
    while num:
        # if (num & 1) = 1
        if (num & 1):
            strs += "1"
        # if (num & 1) = 0
        else:
            strs += "0"
        # right shift by 1
        num >>= 1
    return strs
 
# function to reverse the string
def reverse(strs):
    print(strs[::-1])
 
# Driver Code
num = 67
print("Binary of num 67 is:", end=" ")
reverse(DecimalToBinary(num))

Binary of num 67 is: 1000011

Notes

Inequalities are normal (= is after <> things for equal/less than) (!= is unequal)
boolen is similar to binary, its just true or false
operators
conditions affects the flow of a program and can alow things only when a requirement is met
if/else or if/elif/else
nested conditionals are conditionals within a conditional

print("True:",4 == 4)
print("True:",1 != 0)
print("False:",7 == 3)
print("True:",5 != 6)
print("False:",7 == 8)
print("True:",3 == 3)
print('why is this empty?')

# Same as above, but now for other values other than int
print('True:',"as"=="as")
print("False:",True == False)
print("False:",[2,3,1]!=[2,3,1])
print("True:",'af'!='bc')
print("False:",'ce'=='cf')
print("True:",[1,'b']!=[1,'a'])
print('why is this empty too?')

True: True
True: True
False: False
True: True
False: False
True: True
why is this empty?
True: True
False: False
False: False
True: True
False: False
True: True
why is this empty too?

print("True:", True or False)
print("False:", not True)
print("True:", True and True)
print("False:",  not True)
print("False:", True and False)
print("True:",  not False)

True: True
False: False
True: True
False: False
False: False
True: True

print( 3 3 4 6 5 7)

number = 7
if number == 5: 
    print("5")
else: 
    print("not 5")
    if number <= 3: 
        print("less than 3")
    else: 
        print("not less than 3")
        if number <= 7: 
            print("less than 7")
        else:
            print("not less than 7")
            if number > :
                print("big")
            else: 
                print("7")

not 5
not less than 3
greater than 3

My Solution to the Homework:

def convert(temp):
    value = []
    temp = float(temp)
    i = 0
    while temp > 0:
        if temp % 2 == 0:
            value.append(0)
            temp = temp / 2
        else:
            value.append(1)
            temp = temp /2
            temp = temp - 0.5
        i = i + 1
    final = ""
    x = len(value) - 1
    print("This number is",x+1,"binary digits long.")
    print("This means that your number is",x+1,"bit.")
    while x >= 0:
        final = final + str(value[x])
        x = x - 1
    print(final)
        
ssalcsihtetahi = input("Type a number.")
print(ssalcsihtetahi)
convert(ssalcsihtetahi)

6
This number is 3 binary digits long.
This means that your number is 3 bit.
110